Quadrilateral BCDE is a rhombus and mZBCE = C - 73°. What is the value of c?​

Answer:C=98°Step-by-step explanation:Given:[tex]m\angle EBC= 130\°[/tex]Property of Rhombus to be used:Opposite angles are congruent and diagonals bisect the angles at the corners.[tex]\therefore m\angle EBC=m\angle EDC =130\°[/tex]and [tex]m\angle BED=m\angle DCB[/tex]We know that angle sum of all 4 interior angles =360°[tex]\therefore m\angle EBC+m\angle EDC+m\angle BED+m\angle DCB=360\°[/tex][tex]\therefore m\angle BCD=m\angle BED=\frac{360-(130+130)}{2}=\frac{360-260}{2}=\frac{100}{2}=50\°[/tex][tex]m\angle BCE=\frac{\angle BCD}{2}[/tex] [As diagonal bisect the angles at the corners][tex]m\angle BCE=\frac{50}{2}[/tex]∴ [tex]m\angle BCE=25\°[/tex] [tex]m\angle BCE= C-73\°[/tex]We solve for [tex]C[/tex]Plugging [tex]m\angle BCE=25\°[/tex] and dding [tex]73\°[/tex] to both sides [tex]25+73= C-73+73[/tex][tex]98= C[/tex][tex]\therefore C=98\°[/tex]